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3 years ago

15

How do you break down this problem?

1 answer:

ozzi3 years ago

8 0

What do you mean
Could you please insert an equation or a problem

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A model of a building is made using a scale of 1 inch = 20 feet. What is the height of the actual building, in feet, if the heig

dezoksy [38]

Answer:

210.

Step-by-step explanation:

10.5 x 20 = 210

i hope that helps!!!

4 0

3 years ago

HURRY TIMED QUIZ!! ABCD is a rhombus. Find the length of AC. <br> A.20<br> B.30<br> C.26<br> D.16

Inessa05 [86]

Answer:

26

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A scale drawing of a building needs to be made using the scale 1 inequals=270270 ft. How tall will the building in the scale dra

nadezda [96]

Answer:

and i oop

Step-by-step explanation:

4 0

3 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

PLEASE HELP ME! THE QUESTION IS DOWN BELOW IN THE PICTURE

maria [59]

5 = log(0.9) 0.59045

exponential form:

(0.9)^5 = 0.59045

6 0

3 years ago