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Dovator [93]
3 years ago
9

1. Express the product of 2x2 + 7x – 10 and x + 5 in standard form.

Mathematics
2 answers:
Elis [28]3 years ago
6 0

Answer:

Step-by-step explanation:

It will be easier if you bring that binomial in-front, imo. But the main thing you want to do here is actually really easy. You have to distribute that x to every single term in the trinomial, then do the same thing for the 5. Add up everything.

Distribute the x and 5 like this:

x(2x^2+7x-10) + 5(2x^2+7x-10)

2x^3+7x^2-10x+10x^2+35x-50

Now combine like terms:

2x^3+17x^2+25x-50

There's your answer. Btw, standard form means the exponents are in order high to low and all variables before constants

Vladimir79 [104]3 years ago
4 0
Step 1: Start with the following:
(a + b + c)(d + e)

Step 2: Distribute (d + e) to each of the term in the first parenthesis
a(d + e) + b(d + e) + c(d + e)

Step 3: Distribute d and e to each term:
(ad + ae) + (bd + be) + (cd + ce)
or ad + ae + bd + be + cd + ce without the parentheses.

Step 4: Finally, simplify.
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The correct answer is 5/16.
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2 years ago
Using Substitution solve: y=x+5<br> 4x+y=20
Vladimir [108]

Answer:

3

Step-by-step explanation:

So first, plugin y to your equation, it should look like this: 4x+x+5+20. Now, we can solve this. Next, we have two x's so we can combine them. The equation will now look like this: 5x+5=20. Now, we have an extra 5 laying around that we need to get rid of, so we can subtract that 5 to both sides of the equation and we get this: 5x-5=20-5 which ends up being 5x=15. Now, we just divide both ides by 5 and since 15 divided by 5 is 3, we get: x=3

4 0
3 years ago
if you need to know the amount of frosting to put on the outside of the brownies you need to know perimeter area volume which on
kompoz [17]
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5 0
3 years ago
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What is equivalent too 48j +36
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7 0
2 years ago
Suppose that $a$ is a positive integer for which the least common multiple of $a+1$ and $a-5$ is $10508$. What is $a^2 - 4a + 1$
Nana76 [90]

Answer:

21022.

Step-by-step explanation:

Find the prime factors of 10508:

2 ) 10508

2 ) 5254

37 ) 2627

       71.

50208 = 2*2*37*71.

Now there is no integer value for a that would fit  (a+ 1)(a - 5) = 10508 .

But we could try multiplying the LCM by 2:-

= 21016  = 2*2*2*37*71.

= 2*2*37 multiplied by 2 * 71

= 148 * 142.

That looks promising!!

a - 5 = 142 and

a + 1 = 148

This gives  2a - 4 = 290

2a = 294

a = 147.

So substituting a = 147 into a^2 - 4a + 1 we get:

= 21022.

4 0
3 years ago
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