Question

Use the parabola tool to graph the quadratic function. f(x)=2x2+4x−16

Answer 1

The answer is (0,-18) (2,0). Sorry it's late

Answer 2

Answer:

Refer the attached figure.

Step-by-step explanation:

Given : Quadratic function $f(x)=2x^2+4x-16$

To find : The graph of the quadratic function using parabola tool?

Solution :

The given function $f(x)=2x^2+4x-16$

First we find the vertex form of the equation

$f(x)=2x^2+4x-16$

Where, a=2 ,b=4 , c=-16

Vertex is $V=(\frac{-b}{2a},f(\frac{-b}{2a}))$

$\frac{-b}{2a}=\frac{-4}{2(2)}=-1$

$f(\frac{-b}{2a})=f(-1)=2(-1)^2+4(-1)-16=-18$

So, The vertex of the equation is (-1,-18)

Now, we find y- intercept by putting x=0 in the equation

$y=2(0)^2+4(0)-16$

$y=-16$

y- intercept (0,-16)

Now, we find x- intercept by putting y=0 in the equation

$2x^2+4x-16=0$

$x^2+2x-8=0$

$x^2+4x-2x-8=0$

$x(x+4)-2(x+4)=0$

$(x+4)(x-2)=0$

$x=-4,2$

x- intercepts are (-4,0) and (2,0)

Placing all the points and plot a graph.

Refer the attached figure below.