The energy of a photon is given by
E = h × v
where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴
Substitute 'h' and 'v' into the formula we have
E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
Functions and equations
We have that:
Let's name each side of it with f(x) and g(x):
Then, we have that:
Then, the answer is C
<h2>
Answer: C</h2>
That's not true. 56 is 10 more than 46. 46 +10 is 56.
This is the same as averaging. You add them and divide by 2.
((m/n) + (p/q))/2 would be a number in between m/n and p/q.
Do note that n and q must be nonzero, but luckily that is a given.
