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Finger [1]
4 years ago
14

Matilda has been studying exponential functions in her algebra class and has started to notice a pattern. For some exponential f

unctions, when she plugs in larger and larger numbers, she gets larger and larger numbers. For others, she gets smaller and smaller numbers. And for some, plugging in larger and larger numbers actually gets her closer and closer to one number. Which of the following exponential functions get closer and closer to one value as you plug-in larger and larger values for x?
Mathematics
1 answer:
alexdok [17]4 years ago
3 0

Answer:

  • <em>Some examples of functions for which plugging in larger and larger numbers actually gets her closer and closer to one number are</em>:

                  y=3(1/x)^5\\\\y=1,500x^{-1}\\\\y=400+1,500x^{-1}

Explanation:

The <em>exponential functions </em>that get larger and larger numbers when you plug in larger and larger numbers are called growing exponential functions and they are those with an exponential rate greater than 1.

              y=A\cdot B^x,\text{ where }A\neq 0,B>0

The <em>exponential functions</em> that get smaller and smaller numbers when you plug in larger and larger numbers are called decaying exponential functions and they are those with a positive exponential rate less than 1.

               y=A\cdot B^x,\text{ where }A\neq 0,0

The <em>exponential functions that  plugging in larger and larger numbers actually gets her closer and closer to one number are those with a negative exponential rate less.</em>

               y=A\cdot B^x,\text{ where }A\neq 0,B

Some examples of this kind of equations are:

  • y=3x^{-5},  or its equivalent form y=3(1/x)^5

When x gets larger and larger, (1/x)^5 gets closer and closer to , and the function gets closer and closer to 0.

If you add a constant to the parent function then the function will get closer and closer to the value of the constant.

For instance, for the function   y=3(1/x)^5+20, plugging in  larger and larger numbers actually gets her closer and closer to 20.

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80 * 80% = 64 So it's not A

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Step-by-step explanation:

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All rational numbers are integers trure or false​
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Find the first three terms of the arithmetic series described. n= 16 aₙ= 15 sₙ= -120.
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Answer:

The first three terms are -30, -27 and -24

Step-by-step explanation:

The formula for nth term of a arithmetic series is given by:

aₙ = a₁ + (n - 1)d

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a₁₆ = a₁ + (16 - 1)d

Where aₙ = a₁₆ = 15. Substitute in the given equation

15 = a₁ + 15d ⇒ Equation (i)

Sum of arithmetic sequence is given by:

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Substitute n = 16 in the above equation:

S₁₆ = 16(a₁ + a₁₆) / 2

Where S₁₆= -120 and a₁₆=15, substitute:

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a₃ = a₁ + (3-1)d

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a₃ = -30 +6

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Tan(A)=42/21=2

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