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Alex787 [66]
3 years ago
9

What is (250*645)+345(879*521)-54(219*5674)

Mathematics
1 answer:
Alona [7]3 years ago
3 0

Answer: -623,397

Step-by-step explanation:

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Choose the equation below that represents the line that passes through the point (7, -2) and has a slope of -3
Norma-Jean [14]

Answer:

Option C

Step-by-step explanation:

All of these equation have a slope of x=-3, as this is the only number that will be acompanied by an x (the slope of a function is the number on the equation that has an X). To know which one of this equations passes through the points (7;-2) we can supplant these numbers on each equation until the result at both sides are equals.

The correct answer is the option c, because if we supplant these numbers (x=7 and y=-2) on the equation, we get an equality.

y + 2  = -3. (x - 7) // -2 + 2 = -3. (7 - 7) //0 = 0

7 0
4 years ago
1 Given the data 21, 13, 13, 37, 13, 23, 25, 15:
insens350 [35]
A. the outlier is 37
B. the mean with the outlier is 20
C. the mean without the outlier is 17.5
3 0
3 years ago
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Jackson was making a poster for his room. He arranged 50 trading cards in the shape of a rectangle on the poster. How many rows
julsineya [31]
Pretty sure it's B because 50 isn't divisible by any of the other choices
4 0
4 years ago
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From a window 20 feet above the ground, the angle of elevation to the top of a building across
Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation:  Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across  the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},

and from the right-angled triangle WAB, we have'

\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0
4 years ago
Suppose that a "code" consists of digits, none of which is repeated. (A digit is one of the numbers 0,1,2,3,4,5,6,7,8,9.) How ma
icang [17]
I think it is even numbers
4 0
4 years ago
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