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Genrish500 [490]
3 years ago
8

the Average of ben’s three tests is 89. Each test is worth 100 points. What score does he have to make on his 4th test to get an

average of 90?
Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

93

Step-by-step explanation:

Let's see what kind of equation we can make with this information.

90=((3×89)+x)/4

90×4=267+x

360-267=x=93

We can make this equation work because every test is worth 100 points.

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A curve in polar coordinates is given by: r=9+3cosθ. Point P is at θ=21π/18 .?
ikadub [295]

Answer:

Step-by-step explanation:

Given that a curve in polar coordinates is given by:

r=9+3cosθ

a) At point P, we have

θ=\frac{21\pi}{18}

Substitute to get

r=9+cos \frac{21\pi}{18}\\=9.3932

b) Cartesian coordinate is

x= rcos \theta=3.6934\\y =r sin \tjeta =8.6365

c) At the origin r =0

when r =0

we have

9+3cos\theta=0\\cos\theta =-3

Since cos cannot take values as -3 it doe snot pass through origin.

6 0
3 years ago
EASY MATH GOOD POINTS
34kurt

Answer:

t = (D/C - 1) (100/r)

Step-by-step explanation:

D = C(1+rt/100)

D/C = 1 + rt/100

D/C - 1 = rt/100

D/C - 1 = t (r/100)

Therfore,

<h2>t = (D/C - 1) / r/100</h2>

Therefore the last option is correct.

<h2><em><u>PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
8 0
3 years ago
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Vitek1552 [10]
It is exponential growth because it says 18.36% "more than" and it can be linear because it does not stay at a constant rate of change. Answer: Exponential growth
Hope this helps!
4 0
3 years ago
If f(x) = (1/9)(9^x) what is f(3)
TiliK225 [7]

Answer:  The required value of f(3) is 81.

Step-by-step explanation:  We are given the following function :

f(x)=\left(\dfrac{1}{9}\right)9^x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the value of f(3).

Substituting x = 3 in equation (i), we get

f(3)\\\\\\=\left(\dfrac{1}{9}\right)\times9^3\\\\=9^2\\\\=81.

Thus, the required value of f(3) is 81.

8 0
3 years ago
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Whose solution strategy would work?
Serjik [45]

Answer:

1452628383763637£838

4 0
3 years ago
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