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Alexxandr [17]
3 years ago
15

Which of the following is an SI base unit for measuring length?

Chemistry
1 answer:
Nikolay [14]3 years ago
5 0
An SI base unit for measuring length would be meters.
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Based on solubility rules what ions in water might interfere with the analysis of calcium ions by precipitation of calcium carbo
Pavlova-9 [17]
First, we must know what happens in the precipitation reaction. This type of reaction is a double replacement reactions. It is consists of two reactant compounds which interchange cations and anions to form two products. One of the products is an insoluble solid called a precipitate. For the precipitation of CaCO₃, there are two consecutive reactions involved:

1. Slaking of quicklime, CaO
    CaO + H₂O ⇒ Ca(OH)₂

2. Precipitation
    Ca(OH)₂ + CO₂ ⇒ CaCO₃ + H₂O

The ions that make up the H₂O molecule are H⁺ and OH⁻. According to solubility rules, the cation (positively charged ion) is likely to be attracted to an anion (negatively charged ion). Together, they form an ionic bond. This type of bond is when there is a complete transfer of electrons between the two. The Ca²⁺ cation lacks 2 electrons, while the anion OH⁻ has an excess 1 electron. In order to be stable, 1 Ca²⁺ ion and 2 OH⁻ ions must combine.

Therefore, the answer is OH⁻ ion.
6 0
3 years ago
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Answer the following questions:
Vera_Pavlovna [14]

Answer:

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4 0
2 years ago
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2 Na + Cl2 --&gt; 2 NaCl<br> What is the mole ratio of sodium to sodium chloride?
Irina18 [472]

Answer: The mole ratio of sodium to sodium chloride 2:2.

Explanation:

As the given reaction equation is as follows.

2Na + Cl_{2} \rightarrow 2NaCl

Here, 2 moles of sodium reacts with 1 mole of Cl_{2} and leads to the formation of 2 moles of NaCl.

This means that 2 moles of sodium gives 2 moles of NaCl on reaction with chlorine.

Hence, the ratio of moles of sodium to sodium chloride is 2:2.

Thus, we can conclude that the mole ratio of sodium to sodium chloride 2:2.

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2 years ago
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The answer is c i have a 3 button mouse C. 
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3 years ago
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In Rutherford's Gold foil experiment, were the alpha particles directed to different areas of the gold foil or only the same spo
MrRissso [65]

Answer:

See explanation

Explanation:

In the Rutherford experiment, alpha particles were directed at the same spot on a thin gold foil.

As the alpha particles hit the foil, most of the alpha particles went through the foil. In Rutherford's interpretation, most of the particles went through because the atom consisted largely of empty space.

However, some of the alpha particles were deflected through large angles, in Rutherford's interpretation, the deflected alpha particles had hit the dense positive core of the atom which he called the nucleus.

This accounted for their scattering through large angles throughout the foil in all directions.

8 0
3 years ago
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