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Alexxandr [17]
3 years ago
15

Which of the following is an SI base unit for measuring length?

Chemistry
1 answer:
Nikolay [14]3 years ago
5 0
An SI base unit for measuring length would be meters.
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What happens when a metal is reduced. Give an example of a metal being reduced
AlexFokin [52]

Answer:

The oxidation number of the metal decreases

2 Al  + Fe₂O₃ → Al₂O₃ + 2 FeO

The metal element iron, is reduced from Fe⁺³ in Fe₂O₃ to Fe⁺² in FeO

Explanation:

When an element gains electron, the element becomes reduced, hence when a metal is reduced, the metal gains electrons, which reduces the oxidation number of the metal

An example of a metal being reduced is;

2 Al  + Fe₂O₃ → Al₂O₃ + 2 FeO

In the above reaction, the iron (III) oxide is reduced to iron (II) oxide by aluminium metal.

6 0
3 years ago
If an atom has no electric charge, what can be said about the number of protons and electrons it contains?
vitfil [10]

then the electrons and protons would have a even amount of negetive electric charges

8 0
3 years ago
Looking for 14-16, hispanic, curly hair, genuinely a nice guy
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Answer:me being a tanned ginger

Explanation: i cant date u

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3 years ago
which count of subatomic particles gives an atom its unique identity as an element, and represents its atomic number? a. the num
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The subatomic particles that identifies an element and also represents its atomic number would be A. The number of protons.
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Problem Page Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.2 g o
stich3 [128]

Answer: 0.0 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of butane

\text{Number of moles}=\frac{5.2g}{58.12g/mol}=0.09moles

b) moles of oxygen

\text{Number of moles}=\frac{32.6g}{32g/mol}=1.02moles

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

According to stoichiometry :

2 moles of butane require 13 moles of O_2

Thus 0.09 moles of butane will require =\frac{13}{2}\times 0.09=0.585moles  of O_2

Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.

Thus all the butane will be consumed and 0.0 grams of butane will be left.

7 0
3 years ago
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