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BaLLatris [955]
4 years ago
8

(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial

ly the helium is immersed in thermal bath with at 250K. Suddenly, the helium is removed from this thermal bath and plunged into a thermal bath at temperature 350K. Determine (a) the increase in the entropy of the helium. (Hint the entropy change for the helium is the same as if it had been taken through this temperature change by a reversible process.) (b) the increase in entropy of the universe. (Answer: 0.032 J/K)

Chemistry
1 answer:
icang [17]4 years ago
3 0

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

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Be sure to answer all parts.
djyliett [7]

The number of moles contained in each of the question are a) 3.935 and b) 0.001165 mol.

<h3>What are moles?</h3>

Moles are a quantity or amount of a substance. Denoted by n.

To calculate moles, mass is divided by the molar mass

n = m/M

mass is divided by the molar mass

a) 230 grams of NaCl

n = m/M

molar mass of NaCl is 58.44 g/mol

n = 230 / 58.44 = 3.935 mol

b) 0.210 g of aspirin

n = m/M

molar mass of aspirin is 180.158 g/mol

n = 0.210 / 180.158 = 0.001165 mol

Thus, the moles are a) 3.935 and b) 0.001165 mol.

Learn more about moles

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4 0
2 years ago
Brass alloy is best described as _______.
Vladimir79 [104]

Answer:

it's mixture

Explanation:

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8 0
4 years ago
Calculate the molarity of 0.060 moles of sodium bicarbonate (NaHCO3) in 1500. mL of solution.
inna [77]

Answer: 0.040 mol/l

Explanation: Molarity c = n/V (Concentration)

c = 0.060 mol / 1,5 l = 0,040 mol/l

5 0
3 years ago
Someone please help me answer this.
pantera1 [17]
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7 0
3 years ago
A 200.0mL flask of unknown gas was placed in a hot water bath. The temperature of the bath was found to be 99 degrees C. The pre
masya89 [10]
A. Mass of the unknown gas.

The mass of the unknown gas is calculated by subtracting the weight of the empty flask from the mass when there was air in it.

      m = 126.593 g - 125.623 g

Simplifying,
     m = 0.97 grams

b. Molar mass of the gas
The molar mass of the gas is calculated by the ideal gas law.

                PV = (m/M)RT

where P is pressure,V is volume, m is the mass, M is the molar mass, R is the universal gas constant, and T is temperature. Substituting the known values to the equation,

     (733 mmHg/760 mmHg/atm)(0.20 L) = (0.97 g/M)(0.0821 L.atm/molK)(99 + 273.15 K)

The value of M in the equation is 153.64 g/mol.

<em>Answer: 153.64 g/mol</em>

8 0
4 years ago
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