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3 years ago

Which corresponds to a pressure of 1.23 atm??

1 answer:

6 0

Atmospheric pressure, sometimes also called barometric pressure, is the pressure exerted by the weight of air in the atmosphere of Earth (or that of another planet)

1 atm is equivalent to = 101325 Pa

= 760 mmHg

= 760 torr

= 1.01325 bar

So 1.23 atm is equal to

= 124629.8 Pa

= 934.8 mmHg

= 934.8 torr

= 1.2462 bar

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A cube of an unknown metal measures 0.250 cm on one side. The mass of the cube is 0.134 g. Which of the following is most likely

rosijanka [135]

Answer:

8.58 g/cm3

Explanation:

density = mass / volume

be attention that the question gives u the length of

one side of the cube so u should calculate the volume

of the cube using your information of math .

1st we calculate the volume of the cube :

V of cube = a 3= axaxa

= 0.250 x0.250 x0.250

= 0.0156 cm3

2nd step

density = mass/volume

= 0.134/ 0.0156 = 8.58 g/cm3

5 0

3 years ago

I NEED HELP ASAP!!! THIS IS A 30 POINT QUESTION!!!

bekas [8.4K]

Answer:

Explanation:

Protein synthesis involves two major steps:

Transcription of the DNA to mRNA (a form of RNA)
Translation of the mRNA molecule into a protein.

Transcription involves the formation of a nucleotide sequence complementary to the DNA molecule, with the pairing of a different base, Uracil, with Guanine instead of the usual Thymine base. This occurs in the nucleus of the cell, and the resulting molecule is known as the mRNA.

This mRNA is transported into the cytoplasm through the nuclear pore for the next step, translation. This is primarily accomplished by ribosomes and tRNA molecules which are present in the cytoplasm of the cell. The result of this step is the generation of a protein molecule.

<h3>Hope this helps</h3>

6 0

2 years ago

Read 2 more answers

The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass to 1 decimal place.

xxMikexx [17]

Answer:

answer-

The relative atomic mass = 204.4

explanation:

Thallium -203 = 30%

Thallium -205 = 70%

Therefore ,

relative mass of thallium = (30×203 + 70×205)/100

relative mass of thallium = (20440)/100

relative mass of thallium = 204.40 amu

Thus,

relative atomic mass of thalium =204.4 ( to 1 decimal place)

6 0

3 years ago

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

2 years ago

A company employs several high school students in its food-packaging factory. All the students are below 17 years of age. Which

leonid [27]

Answer:

Fair Labor Standards Act

Explanation:

It is correct. I just took the test on Clever

8 0

2 years ago

Read 2 more answers