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3 years ago

QUESTION 1. Which of the following is not an example of a polymer?

Chemistry

2 answers:

zlopas [31]3 years ago

6 0

I believe it's C. Amino acid is a monomer not a polymer. Q2 is B. Q3 I believe is A. Q4 is D.

cricket20 [7]3 years ago

3 0

Amino acid is not an example of a polymer.its an monomer whereas
polymer is made up of repeating subunit and is a large molecule and chemical bond exist
so i think option C is correct for the first
2-
A carbon atom is able to form four single covalent bonds because it has four valence electrons in its outermost energy level or outermost shell so to complete its octate it forms four singl covalent bond
3-An organic compound that contains a carbonyl group with a hydroxyl group attached to it is an example of carboxylic acid
4- All of the following release carbon into the atmosphere except the
sedimentation of dead organisms.so in my opinion its the correct one
5-Alcohols has a hydroxyl group -O-H attached to a carbon atom
so i conclude option A is correct for last one

hope it helps

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Which of the following describes a property of water that helps sustain marine life forms?

Mariana [72]

Answer:

Open spaces in water's solid structure makes its solid state less dense than its liquid state.

Explanation:

Water unlike other liquids is special. It contracts when cooled, down to a temperature of 4°C but thereafter begins to expand as it reaches 0°C and turns into ice.
This property is useful for the preservation of marine life in very cold temperatures. During winter, the surface water in water lakes and rivers starts cooling. Upon reaching the temperature of 4°C, the surface water descends to the bottom as it denser.
This help in the maintenance of temperature of the water at the bottom at 4°C. It is in this layer that marine life is sustained.

4 0

3 years ago

Given these reactions, where X represents a generic metal or metalloid 1) H2(g)+12O2(g)⟶H2O(g)ΔH1=−241.8 kJ 1) H2(g)+12O2(g)⟶H2O

Bond [772]

Answer:

ΔH = -793,6 kJ

Explanation:

It is possible to obtain ΔH of this reaction using Hess's law that says you can sum the half-reactions ΔH to obtain the ΔH of the global reaction:

If half-reactions are:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁ = −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂ = +356.9 kJ

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl(g) ΔH₃ = −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄ = −639.1 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅ = −44.0 kJ

The sum of (4) + 4×(3) - (2) - 2×(1) - 2×(5) is:

(4) X(s) + O₂(g) ⟶ XO₂(s) ΔH = −639.1 kJ

+4×(3) 2H₂(g) + 2Cl₂(g) ⟶ 4HCl(g) ΔH = −369,2 kJ

-(2) XCl₄(s) ⟶ X(s) + 2Cl₂(g) ΔH = -356,9 kJ

-2×(1) 2H₂O(g) ⟶ 2H₂(g) + O₂(g) ΔH = +483,6 kJ

-2×(5) 2H₂O(l) ⟶ 2H₂O(g) ΔH = +88.0 kJ

= XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g)

Where ΔH is:

ΔH = -639,1 kJ -369,2 kJ -356,9 kJ +483,6 kJ +88,0 kJ

ΔH = -793,6 kJ

I hope it helps!

5 0

3 years ago

A gas has a pressure of 3.16 atm at STP. I have decided to transfer it to a container that is 3 times larger than the original v

Oliga [24]

Answer:

The new pressure is 1.0533 atm

Explanation:

According to Boyle's Law : The Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.

PV = Constant

P1V1 = P2V2

$P_{1}V_{1}=P_{2}V_{2}$ .....(1)

P1 = 3.16 atm

Accprding to question ,

V1 = V

V2 = 3 V

Insert the value of V1 , V2 and P1 in the equation(1)

$P_{1}V_{1}=P_{2}V_{2}$

$3.16\times V=P_{2}\times 3V$

V and V cancel each other

$3.16=P_{2}\times 3$

$P_{2}=\frac{3.16}{3}$

$P_{2}=1.05atm$

5 0

3 years ago

Diatoms are made of _____, which is used for industrial processes. calcium chitin silica cellulose

Alla [95]

A characteristic feature of diatom cells is that they are encased within a unique cell wall made of silica (hydrated silicon dioxide) called a frustule.

5 0

3 years ago

Read 2 more answers

What is my theoretical yield (in moles) of Potassium Bromide (KBr) if I start with 40 grams of Iron (II) Bromide [FeBr2]? moles

Verizon [17]

The reaction will be: FeBr2 + K --> KBr + Fe
Balancing gives: FeBr2 + 2K --> 2KBr + Fe
The molar mass of FeBr2 is 55.85 + 2*79.9 = 215.65 g/mol.
We divide 40 g / 215.65 g/mol = 0.185 mol FeBr2
Based on stoichiometry:
(0.185 mol FeBr2)(2 mol KBr/1 mol FeBr2) = 0.370 mol KBr

4 0

4 years ago