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bogdanovich [222]
3 years ago
6

Iridium has two naturally occurring isotopes, Iridium-191 and Iridium-193. If the average atomic mass of orodum s 192.217, what

are the average percent abundances of each isotope?
Chemistry
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

The percent isotopic abundance of Ir-193 is 60.85 %

The percent isotopic abundance of Ir-191 is 39.15 %

Explanation:

we know there are two naturally occurring isotopes of iridium, Ir-191 and Ir-193

First of all we will set the fraction for both isotopes

X for the isotopes having mass 193

1-x for isotopes having mass 191

The average atomic mass is 192.217

we will use the following equation,

193x + 191(1-x) = 192.217

193x + 191 - 191x = 192.217

193x- 191x = 192.217 - 191

2x = 1.217

x= 1.217/2

x= 0.6085

0.6085 × 100 = 60.85 %

60.85% is abundance of Ir-193 because we solve the fraction x.

now we will calculate the abundance of Ir-191.

(1-x)

1-0.6085 =0.3915

0.3915× 100= 39.15 %

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Answer:

Explanation:

Answer 1:

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Nickel: 1s2 2s2 2p6 3s2 3p6 3d8 4s2  Rubidium: 1s2 2s2 2p6 3s2 3p6 3d10  4s2 4p6 5s1   Xenon: 1s2 2s2 2p6 3s2 3p6 3d10  4s2 4p6 4d10 5s2 5p6

 

Answer 2:  A. Fluorine B. Calcium  

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Given the reaction: solid sodium reacts with chlorine gas to form solid sodium chloride How many moles of the product result fro
lyudmila [28]

Answer:

number of moles of NaCl produce = 12 mol

Explanation:

Firstly, we need to write the chemical equation of the reaction and balance it .

Na(s) + Cl2(g) → NaCl(s)

The balanced equation is as follows:

2Na(s) + Cl2(g) → 2NaCl(s)

1 mole(71 g) of chlorine produces 2 moles(117  g) of sodium chloride

6 mole of chlorine gas will produce ? mole of sodium chloride

cross multiply

number of moles of NaCl produce = 6 × 2

number of moles of NaCl produce = 12 moles

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3 0
3 years ago
Consider four different samples: aqueous LiBr , molten LiBr , aqueous AgBr , and molten AgBr . Current run through each sample p
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Answer:

a) Aqueous LiBr = Hydrogen Gas

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c) Molten AgBr = Solid Ag

Explanation:

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b) Aqueous AgBr

This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.

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c) Molten AgBr

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