Answer:
Explanation:
The products of this reaction are given by:
Firstly, dichromate anion becomes chromium(III) cation, let's write this change:
The following steps should be taken:
- balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:
- balance oxygen atoms by adding 7 water molecules on the right:
- balance the hydrogen atoms by adding 14 protons on the left:
- balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):
Similarly, tin(II) cation becomes tin(IV) cation:
Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:
Add them together:
Adding the ions spectators:
Answer:
The answer is b, c, d, e
Explanation:
b. 2 N2O5 → 4 NO2 + O2
r = k [N2O5]^2 --> Second-order regarding global reaction
c. 2 HI → H2 + I2
r = k [HI]^2 --> Second-order regarding global reaction
d. 2 N2O → 2 N2 + O2
r = k [N2O]^2 --> Second-order regarding global reaction
e. 2 NO2 → 2 NO + O2
r = k [NO2]^2 --> Second-order regarding global reaction
STRUCTURE OF BROMOUS ACID: H–O–Br=O
<span>In this structure, all the elements have a formal charge of
zero. The formal charge of each element is calculated below: </span><span>
H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
<span>O: 6 – 1/2(4) – 4 = 0</span></span>
Answer:
B. 0.2.
Explanation:
<em>n = mass/molar mass</em>
mass of CaCO₃ = 20 g, molar mass of CaCO₃ = 100.0869 g/mol.
<em>∴ n = mass/molar mass = </em>(20 g)/(100.0869 g/mol) <em>= 0.1998 ≅ 0.2 mol.</em>
<em></em>
<em>So, the right choice is: B. 0.2.</em>
