Question

An electrically isolated object is electrically neutral. What is the charge on the object if you remove three electrons?

Answer 1

Answer:

$+4.8\cdot 10^{-19}C$

Explanation:

The initial charge of the object is zero, since the object is neutral:

Q = 0

When we remove three electrons, we remove a charge of:

$q' = 3 \cdot q_e$

where

$q_e = 1.6\cdot 10^{-19}C$ is the charge of one electron. Substituting,

$q'=3 \cdot 1.6\cdot 10^{-19}C=-4.8\cdot 10^{-19} C$

So, the final charge on the initially neutral object will be

$q=Q-q' = 0 - (-4.8\cdot 10^{-19} C)=+4.8\cdot 10^{-19}C$