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HACTEHA [7]
2 years ago
7

Answer the following questions

Physics
2 answers:
zaharov [31]2 years ago
7 0

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

Can I have brainliest answer pls?

rusak2 [61]2 years ago
4 0
9- the answer is A 10N to left
10- the answer is C no change in the object
Hope this helps! :))
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Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
mamaluj [8]

Answer: 9000 kgm/s

Explanation:

Mass of car = 1500 kg

Speed by which car moves = 6 m/s. Momentum of the car = ?

Recall that:

Linear momentum = Mass x Speed

= 1500kg x 6m/s

= 9000 kgm/s

Thus, the linear momentum of the car is 9000 kgm/s

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3 years ago
For the equation BaCI2 + Na2SO4 > BaSO4 + 2NaCI
Umnica [9.8K]
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How do you measure the wavelength of wave?
Tasya [4]

Explanation:

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An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
stich3 [128]

Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

vf^2 =vi^2+2*a(xf-xi)

vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

  t=√2(xf-xi)/a

 t=3.765×10^-10 s

now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

ΔK=Kf-Ki=>1/2*m*vf^2-1/2*m*vi^2

P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

6 0
3 years ago
PLEASE HELP MEE PLEASE I BEG
TEA [102]

Explanation: (I think)

Plug your values into the momentum equation.

So m1= 63kg

m2 = 10 kg

V1 = 12 m/s

And then plug in your values and solve for your unknown (v2)

8 0
2 years ago
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