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2 years ago

Answer the following questions

Physics

2 answers:

zaharov [31]2 years ago

7 0

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

Can I have brainliest answer pls?

rusak2 [61]2 years ago

4 0

9- the answer is A 10N to left
10- the answer is C no change in the object
Hope this helps! :))

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A car moved 40 km north and 90 km south. What is the displacement of the car?

il63 [147K]

Answer:

A. 50 km south

Explanation:

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3 years ago

Two very large parallel sheets a distance d apart have their centers directly opposite each other. The sheets carry equal but op

andrew-mc [135]

Answer:

(A) F

Explanation:

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3 years ago

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As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff ideal sprin

shepuryov [24]

Answer:

The magnitude of force must you apply to hold the platform in this position = 888.89 N

Explanation:

Given that :

Workdone (W) = 80.0 J

length x = 0.180 m

The equation for this work done by the spring is expressed as:

$W = \frac{1}{2}k_{eq}x^2$

Making the spring constant $k_{eq}$ the subject of the formula; we have:

$k_{eq} = \frac{2W}{x^2}$

Substituting our given values, we have:

$k_{eq} = \frac{2*80}{0.180^2}$

$k_{eq} = 4938.27 \ N.m^{-1}$

The magnitude of the force that must be apply to the hold platform in this position is given by the formula :

$F = k_{eq}x$

$F = 4938.27*0.180$

F = 888.89 N

6 0

3 years ago

Force F = (-6.0 N)ihat + (2.0 N) jhatacts on a particle with position vector r =(4.0 m) ihat+ (4.0 m) jhat.

finlep [7]

Answer:

$\tau=(-32k)\ N-m$

$\theta=116.55^{\circ}$

Explanation:

Given that.

Force acting on the particle, $F=(-6i + 2.0j)\ N$

Position of the particle, $r=(4i+4j)\ m$

To find,

(a) Torque on the particle about the origin.

(b) The angle between the directions of r and F

Solution,

(a) Torque acting on the particle is a scalar quantity. It is given by the cross product of force and position. It is given by :

$\tau=F\times r$

$\tau=(-6i + 2.0j)\times (4i+4j)$

$\tau=\begin{pmatrix}0&0&-32\end{pmatrix}$

$\tau=(-32k)\ N-m$

So, the torque on the particle about the origin is (32 N-m).

(b) Magnitude of r, $|r|=\sqrt{4^2+4^2}=5.65\ m$

Magnitude of F, $|F|=\sqrt{(-6)^2+2^2}=6.324\ m$

Using dot product formula,

$F{\circ}\ r=|F|.|r|\ cos\theta$

$cos\theta=\dfrac{F{\circ} r}{|F|.|r|}$

$cos\theta=\dfrac{-24+8}{6.324\times 5.65}$

$\theta=116.55^{\circ}$

Therefore, this is the required solution.

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3 years ago

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What information and measurements would you need to calculate the rate of movement?

aliina [53]

When you talk about rate, you will expect that it will be in terms of a time unit. It measures how fast it is going. So, you would expect that the denominator is in time units. For the movement, you can measure this with either distance or velocity.

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3 years ago