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Sholpan [36]
3 years ago
5

What difficulty will you encounter if you only have data from two recording station?

Physics
2 answers:
denpristay [2]3 years ago
6 0

<span>If you have only two data from two recording stations then you will be having a hard time finding the correct location of the epicenter. This is because triangulation method requires 3 recording station. If you have 2 recording station, the 2 circles will intersect at 2 points giving you 2 locations that could possibly be the epicenter.</span>

Zarrin [17]3 years ago
3 0

Answer:

The seismic data are often recorded using seismograph, that records the arrival of the P and S waves during an earthquake. This seismograph is used to locate the epicenter of an earthquake. During an earthquake, the seismographs placed in the nearby regions records the data regarding these seismic waves, and generates a circle.  

When three seismographs placed at three different locations forms three circles due to an earthquake, it intersect at a common point. This intersecting point is the approximate location of the epicenter. It is a very much efficient and are commonly used.

But when there are only two recording stations, then it becomes difficult to determine the epicenter because two seismographs at two different location can form two circles after recording the data and this two circle will intersect each other at two different point. As a result of which the difficulties will arise in locating the epicenter.

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a) Density of the liquid: 823.5kg/m^3

b) Weight of the liquid: 1372 N

Explanation:

Translation of the text:

<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>

<em>a) the density of the liquid; </em>

<em>b) the weight of the liquid."</em>

a)

We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as

M=m_L + m_V (1)

where

m_L is the mass of the liquid

m_V is the mass of the vessel

We also know that the total mass M is 5 times the mass of the empty vessel, so we have:

M=5m_V\\m_V=\frac{M}{5}=\frac{175}{5}=35 kg

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Therefore, we can find the mass of the liquid only using (1):

m_L=M-m_V=175-35=140 kg

The density of the liquid is given by

d=\frac{m}{V}

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m = 140 kg (mass of the liquid)

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d=\frac{140}{0.170}=823.5kg/m^3

b)

The weight of a body is given by

F=mg

where

m is its mass

g is the acceleration due to gravity

For the liquid in this problem, we have

m = 140 kg (mass)

g=9.8 m/s^2 (acceleration due to gravity)

Therefore, its weight is

F=(140)(9.8)=1372 N

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

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