Answer:
The height of the cone is h = 27
Step-by-step explanation:
<u>Formula:</u>-
Step 1:-
The volume of the cone is 
Given volume is V= 45 in^ 3
Given base of the cone is B= 5 in^2
<u>Step 2</u>:-
by using formula, we get solution

cross multiplication, we get

now simplification, the height of the cone is h = 27
9514 1404 393
Answer:
18 in
Step-by-step explanation:
The volume of each container is the product of its dimensions:
V = LWH
We can let h represent the unknown height of Container 2. The volumes are equal when ...
32·18·12 = 24·16·h
(32·12·18)/(16·24) = h =18 . . . . . divide by the coefficient of h, simplify
The missing height of Container 2 is 18 inches.
Put the equation in standard linear form.

Find the integrating factor.

Multiply both sides by
.

Now the left side the derivative of a product,

Integrate both sides.

On the right side, integrate by parts.

Solve for
.

Answer:
Step-by-step explanation:
-8/9 is the reciprocal i believe
Answer: D
Step-by-step explanation:
Standard Deviation σ2 =
Σ(xi - μ)2/N
=(1 - 5.3)2 + ... + (9 - 5.3)2/10
=68.1/10
= 6.81
σ = √6.81
= 2.60959767014
B) σ2 =
Σ(xi - μ)2/N
=(3 - 61.7)2 + ... + (99 - 61.7)2/10
=58414.1/10
= 5841.41
σ = √5841.41
= 76.429117488036
C) (1 - 11.4)2 + ... + (1 - 11.4)2/10
=8758.4/10
= 875.84
σ = √875.84
= 29.59459410095
D) (79 - 79)2 + ... + (79 - 79)2/10
=0/10
= 0
σ = √0
= 0
I hope this helps, mark as Brainliest please.