Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
- 
, where
and 
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴ 
and 
∴ 
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
Answer: The answer is 0.18
Step-by-step explanation:
I took the test
Answer:
p= 1/3 or 0.33 repeating
Step-by-step explanation:
5-19p=-p-1
5=18p-1
6=18p
divide by 18
6/18 = 1/3 or 0.33 repeating
Answer:
4 better explanation inbox
Step-by-step explanation:
Answer:
Step-by-step explanation:
4u + 8v = -3u + 2v
Solving 4u + 8v = -3u + 2v
Solving for variable 'u'.
Move all terms containing u to the left, all other terms to the right.
Add '3u' to each side of the equation. 4u + 3u + 8v = -3u + 3u + 2v
Combine like terms: 4u + 3u = 7u 7u + 8v = -3u + 3u + 2v
Combine like terms: -3u + 3u = 0 7u + 8v = 0 + 2v 7u + 8v = 2v
Add '-8v' to each side of the equation. 7u + 8v + -8v = 2v + -8v
Combine like terms: 8v + -8v = 0 7u + 0 = 2v + -8v 7u = 2v + -8v
Combine like terms: 2v + -8v = -6v 7u = -6v
Divide each side by '7'. u = -0.8571428571v
Simplifying u = -0.8571428571v
