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Burka [1]
4 years ago
8

Please please please help me with this answer

Mathematics
1 answer:
aleksandrvk [35]4 years ago
8 0

57-29=28 so there is 28 green peppers

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A) (3,2),(2,1)<br><br> B) (3,-2),(-2,1)<br><br> C) (-3,2),(-2,-1)<br><br> D) (-3,-2),(2,-1)
bija089 [108]

Answer:

d

Step-by-step explanation:


4 0
4 years ago
20 Points and markwd brainliest
liberstina [14]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
how long will it take for the pool to completely fill with water? (explain why so i understand) it’s a 120 gallon pool
zhannawk [14.2K]
First, you find out how much can be filled in 1 minute. Then you divide that into 120 to get your answer. 

To find out how much can be filled in 1 minute, take the time and divide it into the volume. We'll use the second row (2 minutes and 8 gallons.)

8/2=4. So it takes 1 minute to fill 4 gallons. Now, you just divide 4 into 120. 

120/4=30

It takes 30 minutes to fill the pool up to 120 gallons. 

3 0
3 years ago
Read 2 more answers
Solve for x: 2 over quantity x plus 2 plus 1 over 5 equals 6 over quantity x plus 5. x = 0 x = −13 x = 13 x = 0 and x = 13
grandymaker [24]

To solve this problem you must apply the proccedure shown below:

1. You have the following expression given in the problem above:

\frac{2}{x+2}+\frac{1}{5}=\frac{6}{x+5}

2. You need to sum the fractions located on the left member, as following:

\frac{10+(x+2)}{5(x+2)}=\frac{6}{x+5}

x=(12+x)(x+5)=6(5x+10)

3. Simplify it and you will obtain a quadratic equation. Solve it by factor out x:

x^{2} -13x=0\\ x(x-13)=0\\ x=0; x=13

Therefore, the answer is: x=0; x=13

4 0
4 years ago
Why can't you factor 2cosx^2+sinx-1=0 ?
Masja [62]
2cos^2x+sinx-1=0\\\\2(1-sin^2x)+sinx-1=0\\\\2-2sin^2x+sinx-1=0\\\\-2sin^2x+sinx+1=0\\\\-2sin^2x+2sinx-sinx+1=0\\\\-2sinx(sinx-1)-1(sinx-1)=0\\\\(sinx-1)(-2sinx-1)=0\iff sinx-1=0\ or\ -2sinx-1=0\\\\sinx=1\ or\ -2sinx=1\\\\sinx=1\ or\ sinx=-\frac{1}{2}\\\\x=\frac{\pi}{2}+2k\pi\ or\ x=-\frac{\pi}{6}+2k\pi\ or\ x=\frac{7\pi}{6}+2k\pi\ where\ k\in\mathbb{Z}
6 0
4 years ago
Read 2 more answers
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