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djyliett [7]
3 years ago
6

10. Solve the system algebraically for x. y = 4.x - 3x - 5 y = 6x + 4

Mathematics
1 answer:
Lunna [17]3 years ago
7 0

Answer:

x= -9/5, y= 34/5

Step-by-step explanation:

:) hope you get it right!~

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Does (5, 10)make the inequality y ≥ 10x+5 true
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Answer:

It is False.

Step-by-step explanation:

When you substitute the coordinates into the inequality equation :

y \geqslant 10x + 5

let \: x = 5,y = 10

10 \geqslant 10(5) + 5

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Therefore, 10 isn't greater than 55.

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3 years ago
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Step-by-step explanation:

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4 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

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\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

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2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

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Answer:

Manau, kad tai D.

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