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Anarel [89]
3 years ago
11

Which best explains why ionization energy tends to decrease from the top to the bottom of a group?

Chemistry
2 answers:
kiruha [24]3 years ago
8 0
The answer would be that the Electrons get farther from the nucleus.  As you go down a group, the Period is increasing, which means that each time a shell is being added on as such the valence electron are moving further away from the nucleus.  It is therefore easier for the valence electron to be removed thus why less energy is needed to remove that electron, thus a decrease in ionization energy.
JulijaS [17]3 years ago
7 0

Answer:

it's D on edgenuity

Explanation:

just took the test

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Acetic acid, CH3CO2H, reacts with ethanol, C2H5OH, to form water and ethyl acetate, CH3CO2C2H5. The equilibrium constant for thi
Irina-Kira [14]

Explanation:

The initial concentrations for a mixture :

Acetic acid at equilibrium = 0.15 M

Ethanol at equilibrium = 0.15 M

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CH3COOH + C_2H_5OH\rightleftharpoons CH_3CO_2C_2H_5+H_2O

Initially:

0.15 M            0.15 M            0.40 M   0.40 M

At equilibrium

(0.15-x)M       (0.15-x) M     (0.40+x) M   (0.40+x) M

The equilibrium constant is given by expression

K_c=\frac{[CH_3CO_2C_2H_5][H_2O]}{[CH_3COOH][C_2H_5OH]}

4.0=\frac{(0.40-x)\times (0.40-x)}{(0.15+x)\times (0.15+x)}

Solving for x:

x = 0.0333

The equilibrium concentrations for a mixture :

Acetic acid at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M

Ethanol at equilibrium = (0.15-x)M = (0.15-0.033) M = 0.117 M

Ethyl acetate at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M

Water at equilibrium = (0.40+x)M = (0.40+0.033) M = 0.433 M

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