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lord [1]
2 years ago
11

when propene gas (C3H6) is added to bromine liquid, another liquid is produced which has the formula C3H6Br2. what is the chemic

al equation/formula​
Chemistry
1 answer:
klio [65]2 years ago
4 0

Answer:

C3H6 + Br2 → C3H6Br2

Explanation:

The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:

  • C3H6 + Br2 → C3H6Br2

We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.

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Lithium (Li): 1s 2sB<br> A=<br> B=
topjm [15]

Answer:

A = 2

B = 1

Explanation:

The atomic number of lithium is 3.

Its atomic mass is 7 amu.

It is present in group group 1.

It has one valance electron.

Lithium is alkali metal it form salts.

It is silvery soft metal. It has lowest density as compared to all other metals.

It react vigorously with water.

It is used in rechargeable batteries which are used in camera, mobile, laptops etc.

The electronic configuration of Li:

Li₃ = 1s² 2s¹

Thus,

A = 2

B = 1

8 0
2 years ago
If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(you will n
Harman [31]

Sodium(Na) is the limiting reagent.

<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

How do you identify a limiting reagent?

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

Start by writing the balanced chemical equation that describes this reaction

2Na_{(s)} + Cl_{2 (g)} -- > 2NaCl_{(s)}

Notice that the reaction consumes 2 moles of sodium metal for every 1 mole of chlorine gas that takes part in the reaction and produces 2 moles of sodium chloride.

now we can see that we have 3 moles of sodium and 3 moles of chlorine, according to question. so, we can say that sodium is the limiting reagent in the given situation.

to learn more about Limiting Reagent go to - brainly.com/question/14222359

#SPJ4

4 0
1 year ago
How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?
stiks02 [169]

Answer:

\large \boxed{\text{12.3 mol HCl}}  

Explanation:

We need a balanced chemical equation with moles.

            2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol:    12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

\text{Moles of H$_{2}$O} = \text{12.3 mol HCl} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces $\large \boxed{\textbf{12.3 mol HCl}}$}

3 0
3 years ago
Write application of isotopes .
SCORPION-xisa [38]

Answer:

In the chemical industry.

6 0
2 years ago
Read 2 more answers
Which of the following reactions should have the larger emf under standard conditions? Why?
miskamm [114]

Answer:

Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)

Explanation:

If we look at the both reactions closely, we will quickly discover that the reaction CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) involves PbSO4.

The compound PbSO4 is insoluble in water and sinks to the bottom of the reaction vessel. When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.

On the other hand, Pb(NO3)2 is soluble in water hence the cell voltage in this case is higher than the former.

7 0
2 years ago
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