You would have one tenths (1/10) of a chance to get a 4 on the first go. you would have four ninths (4/9) of a chance to get a number less than 5 out of the bag on the second go.
the overall probability would be two forty-fifths (2/45)
Yes, they both are 2/7
Proof: Left-hand side
Simplify the following:
12/42
The gcd of 12 and 42 is 6, so 12/42 = (6×2)/(6×7) = 6/6×2/7 = 2/7:
Answer: 2/7
Right-hand side:
Simplify the following:
10/35
The gcd of 10 and 35 is 5, so 10/35 = (5×2)/(5×7) = 5/5×2/7 = 2/7:
Answer: 2/7
Subtraction
161616+444= 162,060
Answer:
0.7 = 70%.
Step-by-step explanation:
There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:
C(5,2) = 5!(3!*2!) = 5*4/2 = 10
To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:
There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:
C(3,2) = 3!/2! = 3
So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7
Then, the probability is 7 / 10 = 0.7 = 70%.
