All categories

3 years ago

Can someone help me with this both parts btw

Mathematics

2 answers:

svetlana [45]3 years ago

7 0

Answer:

c-88=405 c=493

Step-by-step explanation:

Allushta [10]3 years ago

3 0

Answer:

It is c-88=405 trust me :D

Step-by-step explanation:

*whispers* It doesn't hurt to give brainliest, I only need one more for my next tier, can I have it?

You might be interested in

Which of the following represents a geometric series (remember what a series is as opposed to a sequence)?

juin [17]

Answer:

4 + 12 + 36 + ...

Step-by-step explanation:

4, 12, 36, ... is a geometric sequence, it has a common ratio of $r=\frac{36}{12}=\frac{12}{4}=3$

When we add the terms of a geometric sequence we get a geometric series.

4+12+36+ ... is a geometric series, it has a common ratio of $r=\frac{36}{12}=\frac{12}{4}=3$

4 + 12 + 20 + ... is not a geometric series because it has no common ratio

$\frac{20}{12}\ne \frac{12}{4}$

The second choice is correct

8 0

3 years ago

Henry has a faulty watch. It is losing minutes every day. How many minutes will be lost after 7 days?

Ann [662]

A I think this is the answer but I’m not sure

6 0

2 years ago

Read 2 more answers

Which is true about characterization?

Vanyuwa [196]

C.Playwrights can reveal characterization both directly and indirectly

6 0

3 years ago

A carpenter makes and sells rocking chairs. The material for each chair costs $22.50. The chairs sell for $75 each. If the charp

Lady_Fox [76]

Answer:

About 6 chairs

Step-by-step explanation:

75x=22.50+420

75x=442.5

x=5.9

So about 6 chairs

4 0

3 years ago

Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8

oee [108]

Answer:

$f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }$

Step-by-step explanation:

$f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}$

3 0

3 years ago