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9966 [12]
3 years ago
11

Simplify. please and thank you

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

( - 2) {}^{ - 3 }  \\  ( \frac{1}{ { - 2}^{3} }) \\ \frac{1}{ - 2 \times  - 2 \times  - 2 }  \\  \frac{1}{4 \times  - 2}  \\  \frac{1}{ - 8}

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Step-by-step explanation:

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What are the solutions to the equation?<br> 7x^3=28x
11Alexandr11 [23.1K]

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When you have x and different powers, set the whole thing equal to zero.

7x³ = 28x

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x (7x² - 28) = 0

As 7 is a factor of 7 and 28, it too can be factored out.

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We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.

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Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.

x = 0        -----> so x = 0

7 = 0       -----> no solution

x - 2 = 0   ----> so x = 2   after adding 2 to both sides

x + 2 = 0  ---> so = x - 2  after subtracting 2 to both sides


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