Question

What is the molarity of a sucrose solution containing 34.2 grams of sucrose in 500.0 mL of water? The molar mass of sucrose, C12H22O11 , is 342.0 grams per mole.

Answer 1

0.2 M is the molarity of a sucrose solution containing 34.2 grams of sucrose in 500.0 ml of water.

Explanation:

Data given:

mass of sucrose = 34.2 grams

volume of water = 500 ml or 0.5 Litres

molar mass of sucrose = 342 grams/mole

molarity = ?

To calculate molarity first we will calculate number of moles provides,

number of moles = $\frac{mass}{ato,ic mass of 1 mole}$

putting the values in the equation:

number of moles = $\frac{34.2}{342}$

number of moles = 0.1 mole

now the molarity will be calculated by applying the following formula:

molarity = $\frac{number of moles}{volume in litres}$

putting the values in the equation:0.2 m

molarity = $\frac{0.1 }{0.5}$

molarity = 0.2 M

thus the molarity of sucrose solution of 500 ml is 0.2 M