Answer: The activation energy Ea for this reaction is 22689.8 J/mol
Explanation:
According to Arrhenius equation with change in temperature, the formula is as follows.
![ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]](https://tex.z-dn.net/?f=ln%20%5Cfrac%7Bk_%7B2%7D%7D%7Bk_%7B1%7D%7D%20%3D%20%5Cfrac%7B-E_%7Ba%7D%7D%7BR%7D%5B%5Cfrac%7B1%7D%7BT_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7BT_%7B1%7D%7D%5D)
= rate constant at temperature
= 
= rate constant at temperature
=
= activation energy = ?
R= gas constant = 8.314 J/kmol
= temperature = 
= temperature = 
Putting in the values ::
![ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]](https://tex.z-dn.net/?f=ln%20%5Cfrac%7B4.8%5Ctimes%2010%5E8%7D%7B2.3%5Ctimes%2010%5E8%7D%20%3D%20%5Cfrac%7B-E_%7Ba%7D%7D%7B8.314%7D%5B%5Cfrac%7B1%7D%7B649%7D%20-%20%5Cfrac%7B1%7D%7B553%7D%5D)

The activation energy Ea for this reaction is 22689.8 J/mol
Answer:
Two water molecules contain 4 hydrogen atoms and 2 oxygen atoms. A mole of water molecules contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms.
Explanation:
Answer:
Explanation:
Alkyl groups are those which are derived from alkane by the removal of one hydrogen atom
For example ,methane CH4, and its corresponding alkyl groups is methyl -CH3
The question is incomplete, here is the complete question:
A chemistry student needs 75 g of thiophene foran experiment. He has available 0.50 kg of a 29.3% w/w solution of thiophene in carbon tetrachloride.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
<u>Answer:</u> The mass of solution the student should use is 255.97 grams
<u>Explanation:</u>
We are given:
Mass of thiophene needed = 75 gram
29.3 % w/w thiophene solution
This means that 29.3 grams of thiophene is present in 100 grams of solution
Applying unitary method:
If 29.3 grams of thiophene is present in 100 grams of solution
So, 75 grams of thiophene will be present in = 
Given amount of solution = 0.50 kg = 500 grams (Conversion factor: 1 kg = 1000 g)
Hence, the mass of solution the student should use is 255.97 grams