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mojhsa [17]
3 years ago
5

Hamburgers cost $2 and hotdogs cost $2. The total cost of buying b hamburgers and d hotdoge can be expressed by C=3b+2d. how can

equation be solved for d?
Mathematics
1 answer:
sveticcg [70]3 years ago
3 0
C= 3b + 2d
Subtract 3b first.

C-3b = 2d
Divide by 2.

C-3b/2 = d

OR

C-3b
-------- = d Your final answer!
2
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KIM [24]
The answer is b
(-1,3,5)

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8 0
3 years ago
9) The length of segment AE is 12. Find the coordinate of E.
Mashcka [7]

Answer:

-18

Step-by-step explanation:

A is at -30. AE = 12

So, E is -30+12 = -18

6 0
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Betty's Bakery calculates the total price ddd in dollars for ccc cupcakes using the equation d=2cd=2cd, equals, 2, c.
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6 0
3 years ago
Read 2 more answers
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
If JM = 5x – 8 and LM = 2x – 6, which expression represents JL?
Delvig [45]
The green line is LM
The red line is JM
The blue point is at the coordinates (2/3, -14/3)


you'll have to excuse the way my graph looks. my graphing application on my computer is weird 

3 0
3 years ago
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