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nordsb [41]
3 years ago
6

5. What is the multiple zero and multiplicity of f(x) = (x + 4)(x - 2)(x + 4)(x + 4)?

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

The zeros of this functions are -4, 2, -4, and -4.

-4 is a multiple zero and has multiplicity 3.

2 is a zero.  I would call it a simple zero, since it's only a zero once (AKA has multiplicity of 1).

Is this a "pick one answer" or "pick all correct answers"?

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50 x 1000<br> pls reply guys
Firdavs [7]

Answer:

50,000   fifty-thousand

Step-by-step explanation:

Just use a calculator

4 0
2 years ago
Sick-leave time used by employees of a firm in a course of one month has approximately normal distribution, with a mean of 200 h
Usimov [2.4K]

Answer:

a)0.62% probability that total sick leave for next month will be less than 150 hours.

b) 225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 200, \sigma = \sqrt{400} = 20

a.Find the probability that total sick leave for next month will be less than 150 hours.

This probability is the pvalue of Z when X = 150. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 200}{20}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062.

So there is a 0.62% probability that total sick leave for next month will be less than 150 hours.

b.In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

This is the value of X when Z has a pvalue of 0.90. So Z = 1.28

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 200}{20}

X - 200 = 20*1.28

X = 225.6

225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

6 0
4 years ago
What is 130% of 990? Round to the nearest hundredth.
pantera1 [17]

Answer:

1287

Step-by-step explanation:

Is means equals and of means multiply

W = 130% * 990

Change to decimal form

W = 1.30 * 990

W =1287

8 0
3 years ago
Read 2 more answers
What is the partial product for 1,262 x 3
puteri [66]

Step-by-step explanation:

what is THE partial product ? there is a mistake in your problem description.

it must read "what are valid partial products".

1262×3 has the following partial products :

1000×3 = 3000

200×3 = 600

60 × 3 = 180

2×3 = 6

-----------

3786

so, D seems to be the best answer, because both numbers are partial products here.

A, B and C have each only one correct.

7 0
3 years ago
Omar says 0.35 is smaller than<br> 5<br> Explain why he is correct
NISA [10]

Answer:

Because a decimal leading with a zero is always smaller than a whole number

Step-by-step explanation:

7 0
3 years ago
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