Applying the formula for the area of a sector and length of an arc, the value of k is calculated as: 27.
<h3>What is the Area of a Sector?</h3>
Area of a sector of a circle = ∅/360 × πr²
<h3>What is the Length of an Arc?</h3>
Length of arc = ∅/360 × 2πr
Given the following:
- Radius (r) = 9 cm
- Length of arc = 6π cm
- Area of sector = kπ cm²
Find ∅ of the sector using the formula for length of acr:
∅/360 × 2πr = 6π
Plug in the value of r
∅/360 × 2π(9) = 6π
∅/360 × 18π = 6π
Divide both sides by 18π
∅/360 = 6π/18π
∅/360 = 1/3
Multiply both sides by 360
∅ = 1/3 × 360
∅ = 120°
Find the area of the sector:
Area = ∅/360 × πr² = 120/360 × π(9²)
Area = 1/3 × π81
Area = 27π
Therefore, the value of k is 27.
Learn more about area of sector on:
brainly.com/question/22972014
We have:
We know. The line <em>l</em> passes throught the point (9, -7). Substitute the coordinates of the poin to the equation of line<em> l </em>:
Answer: 
You can drag in the first empty box ∡3 and get ∡2≅∡3.
In the second box you can drag '' definition of angle bisector ''.
In the third empy box you can drag ∡1 and get ∡1≅∡3.
At last empy box you can drag ''transitive property of congruence''
Good luck!!!
Hope i am not wrong
f(x)=4x+1
g(x)=x^2-5
(f-g)(x)=f(x)-g(x)
(f-g)(x) =4x+1-x^2+5
-(x^2-6-4x)
solve it for x
Answer: 0
Step-by-step explanation: Anything times 0 is 0
