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WINSTONCH [101]
4 years ago
6

Given BC=EF PROVE AC>EF HELP PLEASE

Mathematics
1 answer:
garik1379 [7]4 years ago
7 0

Answer:

Step-by-step explanation:

BC = EF

AB + BC > EF

Since,

AC = AB + BC

AC > EF

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Step-by-step explanation:

In the figure attached you can see two right triangles  triangle ABD and a triangle ACD.

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The approximate height of the lifeguard station is <em>x</em>.

Keep on mind that:

tan\alpha=\frac{opposite}{adjacent}

Therefore:

<em>For the triangle ABD</em>:

tan(36\°)=\frac{x}{DC+11}    [EQUATION 1]

<em>For the triangle ACD:</em>

tan(46\°)=\frac{x}{DC}    [EQUATION 2]

Solve from DC from [EQUATION 2]:

DC=\frac{x}{tan(46\°)}

Substitute into [EQUATION 1] and solve for x:

tan(36\°)=\frac{x}{(\frac{x}{tan(46\°)}+11)}\\tan(36\°)(\frac{x}{tan(46\°)}+11)=x\\11*tan(36\°)=x-\frac{xtan(36\°)}{tan(46\°)}\\7.991=0.298x

x=26.81ft≈26.8ft

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3 years ago
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