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tensa zangetsu [6.8K]
3 years ago
12

A. How many ways can you make a code of 3 digits if any number can be repeated?

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

1000 ways

First digit of codes: 10 choices (0-9)

Second digit of codes: 10 choices (0-9)

Third digit of codes: 10 choices (0-9)

10*10*10 = 1000

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<h3>Answer:  f( h(x) ) = 2x - 4</h3>

Work Shown:

f(x) = x - 7

f( h(x) ) = h(x) - 7

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Explanation:

In the second step, I replaced every x with h(x). In the next step, I replaced the h(x) on the right hand side with 2x+3. From there I combined like terms.

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Answer:

$7,185 see below ↓

explanation:

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Help me please
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Answer:

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4 years ago
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