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goldenfox [79]
3 years ago
12

At the gym, Tika spends twice as much time doing aerobics than weight training. She stretches for one fifth of the time she spen

ds on weight training. Let w be the amount of time Tika spends on weight training. Which expression represents her total workout?
Mathematics
1 answer:
Dafna1 [17]3 years ago
8 0

Answer:

Her total workout is 2w+w+\frac{w}{5}.

Step-by-step explanation:

Consider the provided information.

Let w be the amount of time Tika spends on weight training.

Tika spends twice as much time doing aerobics than weight training.

It means she spends 2w time doing aerobics.

She stretches for one-fifth of the time she spends on weight training.

It means she spends \frac{w}{5} time for stretches.

The total workout time is:

2w+w+\frac{w}{5}

Hence, her total workout is 2w+w+\frac{w}{5}.

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3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

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t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

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7 0
4 years ago
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we know that


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the longest side of ∆ABC is 4 units


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so

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The ratio of the area of ∆ABC to the area of ∆DEF is \frac{1}{100}

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