Hey there,
Your question states: <span>The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the width of the poster. What are the dimensions of the poster? </span>
Your correct answer would be
Hope this helps.
Answer:
V = 5280 in^3
Step-by-step explanation:
The volume is found by
V = Bh where B is the area of the base and h is the height
first we need to find the area of the base
The base is the triangle
We need to find the base dimension for the triangle
34^2 = 16^2 + b^2
34^2 -16^2 = b^2
900 = b^2
30 =b
B = 1/2 bh
= 1/2 (30) *16
B =240
V = Bh
V = 240 * 22
V = 5280 in^3
Answer:
=========================
<h2>Given </h2>
Triangle with:
- Base of n² -3,
- Midsegment of 39.
<h2>To find</h2>
<h2>Solution</h2>
As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.
So we have:
Solve it for n:
- n² - 3 = 78
- n² = 81
- n = √81
- n = 9
Correct choice is D.
Multiply 0.57 by 51
=29.07
----------------------------------------------------------------------
S = sally C = Chris J = Joe
sally is one year older than 3 times the age of joe, so
s = 3j + 1
chris is 5 years younger than 6 times the age of jo, so
c = 6j - 5
sally and chris are the same age so
s = c so
3j + 1 = 6j - 5
-3j -3j
1 = 3j - 5
+5 +5
6 = 3j or
3j = 6
3j/3 = 6/3
j = 2
check
s = c
3(2) +1 = 6(2) - 5
6 + 1 = 12 - 5
7 = 7 correct✅
