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Lapatulllka [165]
3 years ago
7

Write an equation in slope intercept form

Mathematics
2 answers:
Kamila [148]3 years ago
6 0
y = mx +b is the formula, if you're looking for the slope of a graph or numbers. m is the slope intercept, and b is the y-intercept.

EXAMPLE : y = 6x + 7 — Where y is your answer, 6 is your slope intercept, and 7 is your y-intercept.
Pavel [41]3 years ago
5 0
Y = 3x + 3
The slope is 3 and the y intercept is 3
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a marry go round goes in circulatory motion

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A company has a fleet of 200 vehicles. On average, 50 vehicles per year experience property damage. What is the probability that
ICE Princess25 [194]

Answer:

The probability is \frac{1}{4} or 25%

Step-by-step explanation:

The question states the total number of vehicles, as well as the number of damaged vehicles on a yearly basis. If 50 vehicles in every 200 vehicles per year are damaged, then we can obtain:

Probability of a damaged vehicle in any given year = \frac{Number of Damaged Vehicles}{Total Number of Vehicles}

= \frac{50}{200} = \frac{1}{4} or 25%

4 0
3 years ago
Find the value for x​
d1i1m1o1n [39]

Answer:

Value of x --> 15°

<u>Step-by-step explanation:</u>

(2x + 60°) and 6x lie on a straight line. So, they form a linear pair. Their sum gives 180°.

---> (2x + 60°) + 6x = 180°

     2x + 60° + 6x = 180°

     8x + 60° = 180°

     8x = 180°- 60°

     8x = 120

      x = \frac{120}{8}

<h3><u>x equals 15°</u></h3>
5 0
3 years ago
Hana's height is given as 162 cm, correct to the nearest cm.
SashulF [63]

Answer:

upper is 2 lower Po is 2 step 1 I added after what the answer is that I divide it then that's the answers

6 0
3 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
4 years ago
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