a. Sweet corn and possibly d. okra.
The original Coulomb force between the charges is:
Fc=(k*Q₁*Q₂)/r², where k is the Coulomb constant and k=9*10⁹ N m² C⁻², Q₁ is the first charge, Q₂ is the second charge and r is the distance between the charges.
The magnitude of the force is independent of the sign of the charge so I can simply say they are both positive.
Q₁ is decreased to Q₁₁=(1/3)*Q₁=Q₁/3 and
Q₂ is decreased to Q₂₂=(1/2)*Q₂=Q₂/2.
New force:
Fc₁=(k*Q₁₁*Q₂₂)r², now we input the decreased values of the charge
Fc₁=(k*{Q₁/3}*{Q₂/2})/r², that is equal to:
Fc₁=(k*(1/3)*(1/2)*Q₁*Q₂)/r²,
Fc₁=(k*(1/6)*Q₁*Q₂)/r²
Fc₁=(1/6)*(k*Q₁*Q₂)/r², and since the original force is: Fc=(k*Q₁*Q₂)/r² we get:
Fc₁=(1/6)*Fc
So the magnitude of the new force Fc₁ with decreased charges is 6 times smaller than the original force Fc.
Tennis ball will move with 1/3 th velocity of plastic ball
Answer:
The centripetal acceleration of the car will be 12.32 m/s² .
Explanation:
Given that
radius ,R= 57 m
Velocity , V=26.5 m/s
We know that centripetal acceleration given as follows

Now by putting the values in the above equation we get

Therefore the centripetal acceleration of the car will be 12.32 m/s² .
<u>P.E (Potential Energy) = 33868.8 J</u>
<u>Explanation:</u>
The formula to calculate Potential energy is:
PE = mgh
where PE = potential energy
m = mass of an object
g = acceleration due to gravity
h = height of the object
Here, m = 64 kg
g = 9.8 
h = 54 m
So, substituting the values in the formula:
PE = mgh
= 64 × 9.8 × 54
= <u> 33868.8 J</u>