Ask question

Ask question

All categories

4 years ago

7

A solid plastic ball hits a stationary tennis ball in a perfectly elastic collision. If the mass of the plastic ball is three ti

mes that of the tennis ball, which statement is true?

2 answers:

Iteru [2.4K]4 years ago

8 0

Tennis ball will move with 1/3 th velocity of plastic ball

nataly862011 [7]4 years ago

7 0

Answer:

The two balls split apart but the tennis ball keeps moving

Explanation:

You might be interested in

Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the

Over [174]

Answer:

Part a)

$a= 0.32 m/s^2$

Part b)

$F_c = 3.6 N$

Part c)

$F_c = 5.5 N$

Explanation:

Part a)

As we know that the friction force on two boxes is given as

$F_f = \mu m_a g + \mu m_b g$

$F_f = 0.02(10.6 + 7)9.81$

$F_f = 3.45 N$

Now we know by Newton's II law

$F_{net} = ma$

so we have

$F_p - F_f = (m_a + m_b) a$

$9.1 - 3.45 = (10.6 + 7) a$

$a = \frac{5.65}{17.6}$

$a= 0.32 m/s^2$

Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

$F_c - F_f = m_b a$

$F_c = \mu m_b g + m_b a$

$F_c = 0.02(7)(9.8) + 7(0.32)$

$F_c = 3.6 N$

Part c)

If Alex push from other side then also the acceleration will be same

So for box B we can say that Net force is given as

$F_p - F_f - F_c = m_b a$

$9.1 - 0.02(7)(9.8) - F_c = 7(0.32)$

$F_c = 9.1 - 0.02 (7)(9.8) - 7(0.32)$

$F_c = 5.5 N$

3 0

3 years ago

A bus comes to rest by applying brakes in 10 second calculate the initial velocity of the bus and distance travelled during the

Rina8888 [55]

I dont know the answer to this question

7 0

3 years ago

How does the wind turbine generator work?

AnnZ [28]

Answer: wind pushes directly against the blades of the turbine, which converts the linear motion of the wind into the rotary motion, then it spins the generator's rotor and the harder the wind pushes, the more electrical energy can be generated.

Explanation:

5 0

3 years ago

A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a c

Aneli [31]

Answer

given,

x = (3.9 cm)sin[(9.3 rad/s)πt]

general equation of displacement

x = A sin ω t

A is amplitude

now on comparing

c) Amplitude =3.9 cm

a) frequency =

$f = \dfrac{\omega}{2\pi}$

$f = \dfrac{9.3\pi}{2\pi}$

f = 4.65 Hz

b) period of motion

$T= \dfrac{1}{f}$

$T= \dfrac{1}{4.65}$

T = 0.215 s

d) time when displacement is equal to x= 2.6 cm

x = (3.9 cm)sin[(9.3 rad/s)πt]

2.6 = (3.9 cm)sin[(9.3 rad/s)πt]

sin[(9.3 rad/s)πt] = 0.667

9.3 π t = 0.73

t = 0.025 s

4 0

3 years ago

Read 2 more answers

A common technique in analysis of scientific data is normalization. The purpose of normalizing data is to eliminate irrelevant c

nataly862011 [7]

Answer:

V₂ = 0.4432

Explanation:

The normalize procedure is widely used in science, in this case we are going to normalize to the voltage value that exists 4 cm away

Vₙ= V_{measured} / V₀

where the voltage at the desired distance is V₀ = 185 mV = 0.185 V

the normalized voltage are

forr x = 4 cm

V₁ = 185/185

V₁ = 1

for x = 6.2 cm

V₂ = 82/185

V₂ = 0.4432

3 0

3 years ago