Answer: V1 = 3.559 - 0.744V2
Explanation: Given that the
bumper car A has
Mass M1 = (281 kg) moving with
Velocity U1 = 2.82 m/s
bumper car B has
Mass M2 = (209 kg) moving with
Velocity U2 = 1.72 m/s
Where U1, U2 are the initial velocity of the two cars
Since the collision is elastic, we will use the formula below,
M1U1 + M2U2 = M1V1 + M2V2
Substitute the values into the formula
281×2.28 + 209×1.72 = 281V1 + 209V2
640.68 + 359.48 = 281V1 + 209V2
1000.16 = 281V1 + 209V2
Make V1 the subject of formula
281V1 = 1000.16 - 209V2
V1 = 1000.16/281 - 209V2/281
V1 = 3.559 - 0.744V2
Therefore, the velocity of car A which
is V1 after the collision will be expressed as V1 = 3.559 - 0.744V2
