Complete question:
The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass of 15.0 kg. When the gun fires a projectile with a mass of 0.040 kg and a speed of 380 m/s, what is the recoil velocity of the shotgun and arm–shoulder combination?
Answer:
The recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
Explanation:
Given;
combined mass of the shotgun and arm–shoulder, m₁ = 15 kg
mass of the projectile, m₂ = 0.04 kg
speed of the projectile, u₂ = 380 m/s
let the recoil velocity of the shotgun and arm–shoulder combination = u₁
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = 0
m₁u₁ = - m₂u₂
Therefore, the recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
It represents the depolarization of the atria.
<u>Explanation:</u>
The P wave speaks to the depolarization of the left and right chamber and furthermore relates to atrial compression. Carefully, the atria contract a brief moment after the P wave starts. Since it is so little, atrial repolarization is typically not unmistakable on ECG.
In an ordinary ECG, there's three particular waves. The primary wave is the P wave, which speaks to the depolarization of the atria. This happens directly before the atria agreement and drive blood into the ventricles. The following wave is known as the QRS wave.
Answer:
It would take the cyclist 2 hours to cycle to school.
Explanation:
5km/hr for 2 hours would be 10km.
The car's velocity at time <em>t</em> is given by
It comes to a stop when <em>v</em> = 0, which happens when
or after about 13.9 s.
In this time, the car travels a distance <em>x</em> given by
or about 192 m.
In one complete revolution, each tire covers a distance equal to its circumference,
or about 2.14 m.
This means each tire will complete approximately 192/2.14 ≈ 90 revolutions.
