The snail would travel 100mm
Each minutes is 25mm and it took 4 minutes
4 x 25 = 100
or
25+25+25+25=100
<span>Energy = h nu, where nu is the frequency
h = 6.63 x 10^-34 J-s, Planck's constant
So nu = E/h = 1 x 10^5 J /h = 0.15 x 10^29 / s
nu lambda = c, the speed of light.
lambda = wavelength = c / nu =3 x 10^8 / 0.15 x 10^29 = 20 x 10^-21 m.
this can possibly be a gamma ray. Gamma rays are very penetrating. It's both matter and an energy. They are electromagnetic radiation that results from a radioactive material.
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Answer:
A study looking at how alcohol consumption impacts the brain. A study to discover the components making up human DNA. A study accessing whether stress levels
Explanation:
For example, a scientist that tries to figure out how the body makes cholesterol, or what causes a particular disease, is performing basic scienc
Answer:
Scale reading for no wind 
Explanation:
From the question we are told that
Area 
Weight of board 
Velocity 
Density of air 
Generally the equation for pressure difference by Bernoulli equation is mathematically given by


Generally force acting on the board by air is mathematically given by


Therefore
Scale reading for no wind W'


Scale reading for no wind W'=60N
Answer:
1.16cm were cut off the end of the second pipe
Explanation:
The fundamental frequency in the first pipe is,
<em><u>Since the speed of sound is not given in the question, we would assume it to be 340m/s</u></em>
f1 = v/4L, where v is the speed of sound and L is the length of the pipe
266 = 340/4L
L = 0.31954 m = 0.32 m
It is given that the second pipe is identical to the first pipe by cutting off a portion of the open end. So, consider L’ be the length that was cut from the first pipe.
<u>So, the length of the second pipe is L – L’</u>
Then, the fundamental frequency in the second pipe is
f2 = v/4(L - L’)
<u>The beat frequency due to the fundamental frequencies of the first and second pipe is</u>
f2 – f1 = 10hz
[v/4(L - L’)] – 266 = 10
[v/4(L – L’)] = 10 + 266
[v/4(L – L’)] = 276
(L - L’) = v/(4 x 276)
(L – L’) = 340/(4 x 276)
(L – L’) = 0.30797
L’ = 0.31954 – 0.30797
L’ = 0.01157 m = 1.157 cm ≅ 1.16cm
Hence, 1.16 cm were cut from the end of the second pipe