Question

What is the vertex of the graph of this functiony= -(x-1)(x+3)​

Answer 1

Answer:

Vertex = (-1,4).

Step-by-step explanation:

Given equation is $y=-(x-1)(x+3)$.

Now we need to find the vertex of the graph of given function $y=-(x-1)(x+3)$.

To find that we can rewrite given function into vertex form

$y=-(x-1)(x+3)$

$y=-(x^2+3x-1x-3)$

$y=-(x^2+2x-3)$

$y=-(x^2+2x+1-1-3)$

$y=-((x+1)^2-1-3)$

$y=-((x+1)^2-4)$

$y=-(x+1)^2+4$

Now compar this equation with $y=a(x-h)^2+k$

we get: h=-1, k=4

Hence vertex is (h,k) or (-1,4).