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Alborosie
3 years ago
10

Find the measure of <_A. (show work if possible).

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:

<em>We </em><em>know </em><em>that </em><em>exterior </em><em>angle </em><em>of </em><em>a </em><em>triangle </em><em>is </em><em>equal </em><em>to </em><em>the </em><em>sum </em><em>of </em><em>two </em><em>opposite </em><em>interior </em><em>angle</em><em>.</em>

Step-by-step explanation:

<A = 4y

< B = 3y + 6°

<BCD = 111°

Now

<BCD = <A + <B( exterior angle of a triangle is equal to the sum of two opposite interior angle)

111° = 4y + 3y + 6°

111° - 6° = 7y

105° =7y

Therefore y = 15°

The measure of <A = 4*15°= 60°

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Step-by-step explanation:

  • All these are parallel lines, so the 36° angle is equal to the 36° angle inside the big triangle because they are vertically opposite.

  • Ignore the line cutting between 45° and the 30° and consider it as one triangle
  • Add them to get 75°
  • Now you have two known angles 75° and 36°
  • To get angle <em>x</em><em> </em>add 75° and 36° to get 111°
  • Because x° is an exterior angle and exterior angles equal to the sum of interior angles opposite it inside the triangle.
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