Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
Answer:
29%
Step-by-step explanation:
100%-71%=29%
Answer:
1
Step-by-step explanation:
By gradient, if you mean the "slope" of the linear function, then you have to find two points of the graph and use the "rise over run strategy". Given two coordinates, (x1, y1) and (x2, y2) of a linear function in the form y=mx+b, the slope of the line is (y2-y1)/(x2-x1). This shows the amount of "rise", or the vertical change, and the amount of "run", which is the horizontal change. Rise/Run gives the steepness of the line. The slope can also be modeled by Δy/Δx, which is the change in y over the change in x
Plugging in the given points (0,5) and (-5,0):
(y2-y1)/(x2-x1)= (5-0)/(0-(-5)) = 5/5 = 1
= -(14w + 8) + 8 = 3
= -14w - 8 + 8 = 3
= -14w = 3
w = -3/14
In short, Your Answer would be -3/14
Hope this helps!
