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3 years ago

What is true about a positively charged ion?

Chemistry

1 answer:

Natasha_Volkova [10]3 years ago

8 0

Answer:

The answer to your question is:

Explanation:

Ion is an atom that carries out a positive or a negative charge.

It is formed when an atom loses electrons. Yes, when an atom loses electrons then is formed a positive ion.

It is usually a nonmetallic element. Incorrect. Ions can be form by metallic or non metallic ions.

It has more electrons than protons. Yes, when an atom gains electrons is formed a negative ion.

It is formed when an atom gains protons. I think is incorrect, ions are formed when they gain or lose electrons not protons.

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Which of the following samples had the lowest average kinetic energy?

Aleksandr [31]

Answer:

B. 10 mL of Cabr2(aq) at 35 degrees celsius

Explanation:

The colder something is the more the atoms are compressed together; atoms can't move as much. 35 degrees is the warmest option, so it makes the most sense.

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3 years ago

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How do you draw a bohr diagram for a boron ion?

Otrada [13]

Because Boron likes to lose 3 electrons when it undergoes ionization, we draw a boron ion like a helium atom, with just 2 electrons in the first shell, and 0 in the second

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3 years ago

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What mass of HBO2 is produced from the<br> combustion of 139.5 g of B2H6?<br> Answer in units of g.

aliina [53]

Answer:

$m_{HBO_2}=441.8gHBO_2$

Explanation:

Hello there!

In this case, since the combustion of B2H6 is:

$B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O$

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

$m_{HBO_2}=139.5gB_2H_6*\frac{1molB_2H_6}{27.67gB_2H_6} *\frac{2molHBO_2}{1molB_2H_6} *\frac{43.82gHBO_2}{1molHBO_2}$

$m_{HBO_2}=441.8gHBO_2$

Best regards!

5 0

3 years ago

What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95

melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

$Q = c \times m \times \Delta T$

where,

c: specific heat capacity
m: mass
ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

$Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ$

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

$\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol$

8 0

3 years ago

A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o

azamat

The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg

Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺

The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5

Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
= 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol

Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
= 0.031395 g
= 31.395 mg
≈ 31.4 mg

5 0

4 years ago