1) chromium(III) nitrate is acidic, because it is the salt of weak base (chromium(III) hydroxide Cr(OH)₃) and strong acid (nitric acid HNO₃).
2) sodium hydrosulfide is basic, because it is the salt of strong base (sodium hydroxide MaOH) and weak acid (hydrogen sulfide H₂S).
3) zinc acetate is little basic, because zinc hydroxide (Zn(OH)₂) is stronger base than acetic acid (CH₃COOH).
⁴⁰Ar
N(e)=18
N(p)=18
N(n)=40-18=22
⁴⁰K
N(e)=19
N(p)=19
N9n)=40-19=21
⁴⁰Ca
N(e)=20
N(p)=20
N(n)=40-20=20
Answer:
An oleophilic material is an entity which exhibits a higher affinity for oil than other solvents. The non-polar nature and ability to form cluster-like structures called micelles are the characteristic properties of oleophilic materials.
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As Barium belongs to Group II elements (Alkaine Earth Metals), it has two valence electrons in 6 shell, Hence it capable of loosing two electrons and adopting +2 charge as,
Ba → Ba⁺² + 2 e⁻
And Chlorine belongs to Group VII elements (Halogens), it has seven valence electrons in 3rd shell, Hence it is capable of accepting one electron and adopting -1 charge as,
Cl + e⁻ → Cl⁻
Now, for the formation of Barium Chloride we need 2 chloride ions and one Barium cation, as two -1 and one +2 charge can add to form a neutral molecule. Hence,
Ba⁺² + 2 Cl⁻ → BaCl₂
Answer:
it holds reactant molecules in a good position for then to react