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puteri [66]
3 years ago
8

Please go to this link... I've been waiting for someone to answer for 4 hours...

Chemistry
1 answer:
Charra [1.4K]3 years ago
6 0
On my way! to find the answer
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Match the function to the part of the cell.
Arada [10]
Lysosome is B. breaks down waste materials

Vacuole is A. temporary storage

Chloroplast is C. converts energy
7 0
2 years ago
Is barium nitrate more soluble in water than CH4 or the other way around?
kenny6666 [7]
Barium nitrate and methane (CH4) are both soluble. They both will dissolve in water, however, barium nitrate will dissociate becoming barium 2+ ions and nitrate becoming NO3 1- ions. All nitrates are soluble and dissociate. CH4 is a weak base and does dissolves but doesn't dissociate. So in solubility terms.... they are both equally soluble just one happens to dissociate into its cations and anions. Hope this helps!
3 0
3 years ago
What impact does bleached coral have on the ecosystem in which it lives?
Aloiza [94]

Answer:

Bleached corals are likely to have reduced growth rates, decreased reproductive capacity, increased susceptibility to diseases and elevated mortality rates. Changes in coral community composition can occur when more susceptible species are killed by bleaching events.

8 0
3 years ago
You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.
sergij07 [2.7K]

7.86 \times 10 {}^{23} atoms \\  \frac{7.86}{6.022}  \times  \frac{10 {}^{23} }{ {10}^{23} }   = 1.305\: moles

1.305 × (23+35.5) = 76.34 grams

3 0
3 years ago
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
Likurg_2 [28]

Answer: 281 hours

Explanation:-

1 electron carry charge=1.6\times 10^{-19}C

1 mole of electrons contain=6.023\times 10^{23} electrons

Thus  1 mole of electrons carry charge=\frac{1.6\times 10^{-19}}{1}\times 6.023\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

96500\times 2=193000Coloumb of electricity deposits 1 mole or 63.5 g of copper

0.0635 kg of copper is deposited by 193000 Coloumb

11.5 kg of copper is deposited by=\frac{193000}{0.0635}\times 11.5=34952756 Coloumb

Q=I\times t

where Q= quantity of electricity in coloumbs  = 34952756 C

I = current in amperes = 34.5 A

t= time in seconds = ?

34952756 C=34.5A\times t

t=1013123sec=281hours

Thus it will take 281 hours to plate 11.5 kg of copper onto the cathode if the current passed through the cell is held constant at 34.5 A.

8 0
3 years ago
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