Question

How many molecules of aspirin C9H804 are there in 100.0 MG tablets of aspirin

Answer 1

Answer:

3.34×10³⁰ molecules of C₉H₈O₄

Explanation:

Let's determine the molar mass of aspirin:

C₉H₈O₄ → 12 g/mol . 9 + 1g/mol . 8 + 16g/mol . 4 = 180 g/mol

Let's convert the mass from g to mg → 180 g . 1000 mg/1g = 180000 mg

= 1.8×10⁵ mg

Now, we make a rule of three:

In 1.8×10⁵ mg of aspirin (1 mol) we have 6.02×10²³ molecules

In 100 mg of aspirin, we may have ( 100 . 6.02×10³) / 1.8×10⁵ = 3.34×10³⁰ molecules

Answer 2

Answer:

In 100 mg aspirin there are 3.34*10^20 molecules

Explanation:

Step 1: Data given

Mass of aspirin = 100.0 mg = 0.100 grams

Molar mass of aspirin = 180.158 g/mol

Number of Avogadro = 6.022*10^23 molecules / mol

Step 2: Calculate moles

Moles aspirin = mass aspirin / molar mass aspirin

Moles aspirin = 0.100 grams / 180.158 g/mol

Moles aspirin = 5.55 * 10^-4 moles

Step 3: Calculate molecules aspirin

Molecules = moles * number of Avogadro

Molecules = 5.55 * 10^-4 moles * 6.022 *10^23 molecules / mol

Molecules = 3.34*10^20 molecules

In 100 mg aspirin there are 3.34*10^20 molecules