Answer:
A) 3.17 g of Zn
Explanation:
Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.
Zn⁺²(aq) + 2e⁻ → Zn(s)
We can establish the following relations:
- 1 min = 60 s
- 1 A = 1 C/s
- The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
- When 2 moles of electrons circulate, 1 mole of Zn is deposited.
- The molar mass of Zn is 65.38 g/mol
The mass of Zn deposited under these conditions is:
The correct answer is 2. Magnetic fields must start at the north pole of a magnet and end at the south pole of a magnet. I took the test. Hope I helped!
Answer:
The answer is
<h2>1479.60 mL</h2>
Explanation:
In order to calculate the volume needed we use the formula
where
C1 is the concentration of the stock solution
V1 is the volume of the stock solution
C2 is the concentration of the diluted solution
V2 is the volume of thevdiluted solution
From the question
C1 = 1.45 M
V1 = 25 mL
C2 = 0.0245 M
So we have
We have the final answer as
<h3>1479.60 mL</h3>
Hope this helps you
Answer:
No se bro cual se la respuesta .......
Explanation:
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