Step-by-step explanation:
as the other triangle is Isosceles triangle which means it's two sides are equal and two angles are equal so
to find its 3rd angle apply angles sum property on it
according to which
2(68) + x = 180
136 + x = 180
x = 180 - 136
x = 44°
also we know, the other triangle is right angled triangle
so, it's one angle is 90° and 2nd angle is 44° (Vertically opposite angle)
therefore to know measure of angle 2 apply angle sum property of triangle in it too.
so,
90 + 44 + angle 2 = 180
134 + angle 2 = 180
angle 2 = 180 - 134
angle 2 = 46°
therefore, angle 2 is 46°
hope this answer helps you dear!
Answer:
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Answer:
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- <u><em>Yes, it is reasonable to expect that more than one subject will experience headaches</em></u>
Explanation:
Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."
You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.
- p = 0.732 is the probability of success (an individual experiences headaches).
- n = 5 is the number of trials (number of subjects in the sample).
The meaning of the table of the distribution probability is:
The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.
To answer whether it <em>is reasonable to expect that more than one subject will experience headaches</em>, you must find the probability that:
- X = 2 or X = 3 or X = 4 or X = 5
That is:
- P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5).
That is also the complement of P(X = 0) or P(X = 1)
From the table:
- P(X = 0) = 0.0014
- P(X = 1) = 0.0189
Hence:
- 1 - P(X = 0) - P(X = 1) = 1 - 0.0014 - 0.0189 = 0.9797
That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.
In conclusion, <em>yes, it is reasonable to expect that more than one subject will experience headaches</em>
Answer:
Distance swam by Sonya in 3 weeks = 19740 m
Step-by-step explanation:
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.
Number of days in 1 week = 7
Number of weeks she swam = 3
Total number of days she swam = 3 x 7 = 21 days
Distance swam per day = 0.94 km
Total distance swam = Total number of days she swam x Distance swam per day
Total distance swam = 21 x 0.94 = 19.74 km = 19.74 x 1000 m = 19740 m
Distance swam by Sonya in 3 weeks = 19740 m
