Let's say the numbers are "a" and "b"
thus
![\bf y=ab\qquad \begin{cases} a+b=80\\ b=80-a \end{cases}\implies y=a(80-a)\implies y=80a-a^2\\\\ -----------------------------\\\\ \cfrac{dy}{da}=80-2a](https://tex.z-dn.net/?f=%5Cbf%20y%3Dab%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Aa%2Bb%3D80%5C%5C%0Ab%3D80-a%0A%5Cend%7Bcases%7D%5Cimplies%20y%3Da%2880-a%29%5Cimplies%20y%3D80a-a%5E2%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bda%7D%3D80-2a)
set the derivative to 0, and check the critical points, there's only one anyway
and do a first-derivative test, to see if it's a maximum
12×5=60 3×20=60
60-60=0 So the answer is 0
Answer:
true
Step-by-step explanation:
Please give brainliest
1 equals 3 over 4
2 equals 1 over 6
3 equals 1 over 5
4 equals 1 over 3
5 equals 5 over 11
6 equals 1 over 4
7 equals 1 over 5
8 equals 1 over 9
9 equals 2 over 5
10 equals 1 over 3
Answer:
fx(x)=[(4! /(x!)*(4-x)!]*[(0.3) ^x]*[(0.7) ^ (4-x)]
Step-by-step explanation:
F(x) is been calculated by considering X (moderate) as one outcome and low and high combined as one outcome now probability function will be same as binomial distribution
F(x) = [(4! /(x!)*(4-x)!]*[(0.3) ^x]*[(0.7) ^ (4-x)]