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2 years ago

Displacement is the difference between the initial position and the____ position of an object

1 answer:

4 0

Displacement is the difference between the initial position and the FINAL position of an object.

Hope this helps!

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What happens is a series circuit when you increase the number of bulbs?

Volgvan

The bulbs will produce lesser light than their capacity, In short they will be dimmer because the the energy will get divided in the number of bulbs.

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2 years ago

IF U ANSWER I WILL PUT U AS BRAINIEST ANSWER AND GIVE U A THANK U

Bingel [31]

At the Earth's surface, warm air expands and rises, creating
what is known as an area of low pressure.

Cold air is dense and sinks to the surface to create what is
known as an area of high pressure.

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3 years ago

Read 2 more answers

How many atoms are in SO 3

kkurt [141]

Answer:

There are 6.87 x 1023 atoms in 1.14 mol SO3, or sulfur trioxide :

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3 years ago

A 10 m long clothesline is strung so that it is perfectly horizontal. when a shirt is hung in the exact center the line sags to

Leto [7]

Answer:

x = 0.0873 m

Explanation:

given,

length of clothesline = 10 m

the line sags to create an angle that is 1 degree below the horizontal on each end.

As mass is hang at the center the angle made let the deflection be 'x'

as the shirt is hang at the center distance will be equal to 5 m.

now

$tan \theta = \dfrac{d_e}{d}$

$tan \theta = \dfrac{x}{5}$

$tan 1^0 = \dfrac{W}{5}$

$W = 5 \times 0.0175$

x = 0.0873 m

Hence, the cloth line will be x = 0.0873 m from the original length of the clothesline.

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2 years ago

Star X has an apparent magnitude of 1. Star Y has an apparent magnitude of 4. Both stars are in the same star cluster. Which sta

sashaice [31]

Answer:

Explanation:

From the given information:

Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:

$m_1 - m_2 = -2.5 log _{10} (\dfrac{L_1}{L_2})$

Given that;

m_1 = 1 and

m_2 = 4

Therefore,

$1 - 4 = -2.5 log _{10} ( \dfrac{L_1}{L_2})$

$3 = -2.5 log _{10} ( \dfrac{L_1}{L_2})$

Making $\dfrac{L_1}{L_2}$ the subject of the formula:

$\implies \dfrac{L_1}{L_2}= 10^{(\dfrac{3}{2.5})}$

=15.84

≅ 16

Hence, we can conclude that star X is more luminous by a factor of 16

7 0

2 years ago